# Arup Guha
# 5/31/2012
# Determine if a year is a leap year or not.
# Edited on 6/1/2026 to use Boolean variable.

def main():

    # The current year.
    CURYEAR = 2026

    # Get the year from the user.
    year = int(input("Please enter a year.\n"))

    # Assume we have a leap year, by default.
    result = True

    # If it's not divisible by 4, it's not a leap year.
    if year%4 != 0:
        result = False

    # Also, screen for 1700, 1800, 1900, etc. which are also not leap years.
    elif year%100 == 0 and year%400 != 0:
        result = False

    # MODIFICATION GOES HERE 

    # Print the end result.
    if result:
        print(year,"was a leap year.")
    else:
        print(year,"was not a leap year.")

main()