// Arup Guha
// 6/5/2023
// Alternate Solution to Kattis Problem Cetvrta

using namespace std;
#include <iostream>

int diffVal(int a, int b, int c);
int min3(int a, int b, int c);
int max3(int a, int b, int c);

int main() {

    int x1,y1,x2,y2,x3,y3;

    cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;

    // For each x and y, we want the unique value.
    cout << diffVal(x1,x2,x3) << " " << diffVal(y1,y2,y3) << endl;

    return 0;
}

int diffVal(int a, int b, int c) {
    return 2*min3(a,b,c) + 2*max3(a,b,c) - a - b - c;
}


int min3(int a, int b, int c) {
    if (a<b && a<c) return a;
    else if (b<c) return b;
    return c;
}

int max3(int a, int b, int c) {
    if (a>b && a>c) return a;
    else if (b>c) return b;
    return c;
}