// Arup Guha
// 1/6/2015
// Solution to 2005 MCPC Problem I: Netiquette

import java.util.*;

public class i {

	// Problem constants.
	final public static String INVALID = "suspicious";
	final public static String VALID = "OK";

	public static void main(String[] args) {

		Scanner stdin = new Scanner(System.in);
		String line = stdin.nextLine();

		// Process all cases.
		while (!line.equals("#")) {
			System.out.println(solve(line));
			line = stdin.nextLine();
		}
	}

	// Check each rule and return.
	public static String solve(String input) {
		if (twoAdjacentUpper(input)) return INVALID;
		if (digitNextToLetter(input)) return INVALID;
		if (badIsolatedChar(input)) return INVALID;
		if (twoAdjacentPunc(input)) return INVALID;
		return VALID;
	}

	public static boolean twoAdjacentUpper(String input) {

		// Check all pairs of adjacent spots.
		for (int i=0; i<input.length()-1; i++)
			if (Character.isUpperCase(input.charAt(i)) &&Character.isUpperCase(input.charAt(i+1)))
				return true;
		return false;
	}

	public static boolean digitNextToLetter(String input) {

		// Check all pairs of adjacent spots.
		for (int i=0; i<input.length()-1; i++) {
			if (Character.isDigit(input.charAt(i)) && Character.isLetter(input.charAt(i+1)))
				return true;
			if (Character.isDigit(input.charAt(i+1)) && Character.isLetter(input.charAt(i)))
				return true;
		}
		return false;
	}

	public static boolean badIsolatedChar(String input) {

		for (int i=0; i<input.length(); i++) {
			char c = input.charAt(i);

			// Skip over non-isolated characters.
			if (i > 0 && input.charAt(i-1) != ' ') continue;
			if (i < input.length()-1 && input.charAt(i+1) != ' ') continue;

			// It's bad if it isn't one of these three.
			if (c != 'a' && c != 'A' && c != 'I') return true;
		}
		return false;
	}

	public static boolean twoAdjacentPunc(String input) {

		// Check all pairs of adjacent spots.
		for (int i=0; i<input.length()-1; i++)
			if (isPunc(input.charAt(i)) && isPunc(input.charAt(i+1)))
				return true;
		return false;
	}

	// Returns true iff c is a puncuation character, according to this spec.
	public static boolean isPunc(char c) {
		return !Character.isLetter(c) && !Character.isDigit(c) && !Character.isWhitespace(c) && c != '\"';
	}
}